top of page

CCC 2017 J2: Shifty Sum

Updated: Oct 29, 2020


A for loop that adds the first input times 10 ^ x (x being times looped).

Example: input1 = 12 input2(x) = 3

the anwser will be 12*10^0 + 12*10^1 + 12*10^3 = 12 + 120 + 1200 + 12000 = 13332

Try inputing 12 and 3 yourself!


def shift(a,b):
    ans = 0
    for i in range(b+1):
        ans += a*pow(10,i)
    print(ans)

N = int(input())
M = int(input())
shift(N,M)

Recent Posts

See All

CCC '24 J5 - Harvest Waterloo

#include<iostream> #include <vector> #include <algorithm> #include <cmath> #include <stack> using namespace std; int main() { int r, c, sr, sc; cin >> r; cin >> c; int p[r][c]; bool v

CCC '24 J4 - Troublesome Keys

#include <iostream> #include <string> #include <map> #include <vector> #include <algorithm> #include <cmath> using namespace std; int main() { string ps; string ds; cin >> ps; cin >> ds;

CCC '22 J5 - Square Pool

#include<iostream> #include <vector> #include <algorithm> #include <cmath> using namespace std; bool rowcom(pair<int, int> a, pair<int, int> b){ return a.first < b.first; } bool colcom(pair<int,

Comments


bottom of page