CCC 2017 J2: Shifty Sum

Jul 23, 2020

Updated: Oct 29, 2020

A for loop that adds the first input times 10 ^ x (x being times looped).

Example: input1 = 12 input2(x) = 3

the anwser will be 12*10^0 + 12*10^1 + 12*10^3 = 12 + 120 + 1200 + 12000 = 13332

Try inputing 12 and 3 yourself!

def shift(a,b):
    ans = 0
    for i in range(b+1):
        ans += a*pow(10,i)
    print(ans)

N = int(input())
M = int(input())
shift(N,M)

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